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1.5x^2-4.5x-1680=0
a = 1.5; b = -4.5; c = -1680;
Δ = b2-4ac
Δ = -4.52-4·1.5·(-1680)
Δ = 10100.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.5)-\sqrt{10100.25}}{2*1.5}=\frac{4.5-\sqrt{10100.25}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.5)+\sqrt{10100.25}}{2*1.5}=\frac{4.5+\sqrt{10100.25}}{3} $
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